Volver al curso
Final (1): Ejercicio 18
Video Player is loading.
This is a modal window.
The media could not be loaded, either because the server or network failed or because the format is not supported.
1
Acerca del video
El área de la región encerrada por el gráfico de $f(x) = \sqrt{x}$, la recta $y = 4$ y el eje $y$ se obtiene calculando:
$\circ$ $\int_{0}^{16} \sqrt{x} \, dx$
$\circ$ $\int_{0}^{16} \left( 4 - \sqrt{x} \right) \, dx$
$\circ$ $\int_{0}^{4} \left( 16 - \sqrt{x} \right) \, dx$
$\circ$ $\int_{0}^{2} \left( \sqrt{x} - 4 \right) \, dx$